anas.eng441
2 Answers
Colleen
This is all I could find. It's the closest to the problem you posted. Hope it helps you to figure out the answer.
n = number of resistances
• Have a resistor in parallel is calculated as the inverse of the sum of the inverse of resistance. It sounds complicated but is not. It's just you calculate the inverse of each resistance, add everything and then calculate the inverse of this sum.
1 / R = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn
n = number of resistances
This solution was posted in Portuguese so I had to translate it. Source: http://au.answers.yahoo.com/question/index?qid=20081006082321AAgskVO
| 11 years ago. Rating: 1 | |
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