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When wanting to calculate grams of Na2CO3 produced from 2 grams of NaHCO3 in the reaction 2NaHCO3 --> Na2CO3 + CO<font size="1">2 + </font>H2O, one need to use the molar masses of both Na2CO3 and NaHCO3, which are 106 and 84 gram/mole, respectively, and the their molar ratio from the reaction equation (2 NaHCO3 and 1 Na2CO3):
According to the formula 'number of moles = mass / molar mass', 2 grams of NaHCO3 used in this reaction are 2 grams / 84 grams per mole = 0.0238 moles. Now according to the molar ratio from the reaction equation, calculating how many grams of Na2CO3 are produced is possible (by using the 'number of moles = mass / molar mass' formula).
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