1 Answer
A geometric progression sum: 1/1-r (assuming sequence is r, r^2,...r^n
? this is only valid when you take the limit of the sum of a geometric sequence as {n\rightarrow\infty}, and you need to have the first term of the sequence on the numerator, unless it is exactly 1.
that is
\lim_{n\rightarrow\infty}S_n=\lim_{n\rightarrow\in fty}b_1\frac{1-q^{n}}{1-q}=\frac{b_1}{1-q} for |q|<1 and
\lim_{n\rightarrow\infty}S_n=\infty when |q|>1
12 years ago. Rating: 1 | |
Top contributors in Uncategorized category
Unanswered Questions
Go88 - Sân chơi game bài đổi thưởng hàng đầu.
Answers: 0
Views: 5
Rating: 0
javaliveblog1
Answers: 0
Views: 10
Rating: 0
javaliveblog1
Answers: 0
Views: 11
Rating: 0
iWin | iWin club – Sòng Bạc Thượng Lưu Link tải mới nhất 2024
Answers: 0
Views: 11
Rating: 0
FB88
Answers: 0
Views: 11
Rating: 0
iwinclubpcfsv
Answers: 0
Views: 19
Rating: 0
789win
Answers: 0
Views: 12
Rating: 0
98win - Trang Chủ Chính Thức 98win, 98wincom, 98winclub
> More questions...
Answers: 0
Views: 19
Rating: 0