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    3. The perimeter of a rectangle is 206 inches, the length exceeds the width by 29 inches. Find thge length and the width. the length is
    The perimeter of a rectangle is 206 inches, the length exceeds the width by 29 inches. Find thge length and the width. the length is

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    0  Views: 1136 Answers: 1 Posted: 12 years ago
    Tags: algebra problem algebra problem not good at word problems
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      1 Answer

      your home work is to figure out how I did it...


      width is 37 length is 66        37X2+66X2=206

      12 years ago. Rating: 1
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        chelleanne

        Just stumble upon this question.
        Did you do it this way?

        Set up two equations:

        L = Length
        W = Width

        2L + 2W = 206
        L = W + 29

        Solve for W

        2(W + 29) + 2W = 206
        2W + 58 + 2W = 206
        4W + 58 = 206
        4W + 58 - 58 = 206 - 58
        4W = 148
        4W/4 = 148/4
        W = 37

        Solve for L. Use either equation

        L = W + 29
        L = 37 + 29
        L = 66

        L = 66
        W = 37

        P = 66*2 + 37*2 = 206



        commented 10 years ago


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