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    how do you solve this equation 2x-5=4(9x-2)+71

    0  Views: 1045 Answers: 1 Posted: 12 years ago
    millgate

    Put another way ...

    2X= 4 x ((9X-2) + 71) + 5 or ....

    2X = 36X - 8 + 4x71 +5 or ....

    -34X = -8 + 284 +5 = 281

    thus .... 34X = - 281 or ...

    X = - 281/34 = -8.2647

    At least I think that's how I did it 65 years ago at school !!! (grin)

    1 Answer

    2x - 5 = 4(9x - 2) + 71
    2x - 5 = 36x - 8 + 71
    2x - 5 = 36x + 63
    2x - 5 + 5 + 36x + 63 + 5
    2x = 36X + 68
    2x - 36x = 36x - 36x + 68
    -34X = 68
    x/-34 = 68/-34
    x = -2


    2(-2) - 5 = 4{(9*-2) -2} + 71
    -4  - 5 = 4(-18 - 2) + 71
    -9 = -72 - 8 + 71
    -9 = -80 + 71
    -9 = -9



     

    mrdadguy

    wow no wonder i never took this it makes no sense to me,, my poor kids,, i randomly picked your question, to help my son with an entirely different ?...i.e. in how many ways can you choose 2 side dishes out of 10,,the teachers paper had 45 as an answer, to look in here, the answer is 90,, i cannot undedrstand the path to that
    Bob/PKB

    combine the side dishes as follows:
    1/2, 1/3, 1/4, 1/5, 1/6, 1/7, 1/8, 1/9, 1/10
    2/3, 2/4, 2/5, 2/6, 2/7, 2/8, 2/9, 2/10
    3/4, 3/5, 3/6, 3/7, 3/8, 3/9, 3/10
    4/5, 4/6, 4/7, 4/8, 4/9, 4/10
    5/6, 5/7, 5/8, 5/9, 5/10
    6/7, 6/8, 6/9, 6/10
    7/8, 7/9, 7/10
    8/9 8/10
    9/10


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