mjsent
2 Answers
Bob/PKB
(6a^4 + 6a^3 + 5a^2) / 6a^3
You must first do as much calculating of the parenthesized numbers.
I have to give 'a' some kind of value (It is just easier for me that way.) I'm going to give "a" the value of 5. Then I can get to work.
6(5)^4 = 6(5x5x5x5) = 6(625) = 3750
6(5)^3 = 6(5x5x5) = 6(125) = 750
5(5)^2 = 5(5x5) = 5(25) = 125
3750 + 750 + 125 = 4625
4625 / 6(5)^3 = 4625 / 6(5x5x5) = 4625 / 6(125) = 4625 / 750 = 6.166...
3750/750 = 5 750/750 = 1 625/750 = .83333 (That's how Eggplant's problem would have looked if she'd used "5" for "a"). 5 + 1 + .167 (which is 1/6) = 6.1666 = a + 1 + 1/6
Our answers are a little different and I'm not really sure which is correct. NOTE: I have the correction expression, changing it after eggplant pointed out my mistake.
| 12 years ago. Rating: 1 | |
eggplant
I assume that you have typed the problem correctly without any typing mistakes and you would like to simplify this expression to a simple expression.
(6a^4+6a^3+5a^2)/6a^3
Divide each item in the brackets by 6a^3
(6a^4+6a^3+5a^2)/6a^3 = 6a^4/6a^3 + 6a^3/6a^3 + 5a^2/6a^3 = a + 1 + (5/6a)
Please let me know if you have any questions regarding this problem.
| 12 years ago. Rating: 1 | |
Step 3 in the calculation has the following:
5(5)^3 = 5(5x5x5) = 5(125) = 625
This is wrong as the power in the problem for this step is 2 (not 3). I suppose that this is a careless mistake.
Also, it is not necessary to assume any values for "a", as this problem can be solved easily using basic algebra instead of using arithmatic.