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    4. Ahmad and George had a total of 76 marbles at first. After George bought 15 more marbles and Ahmad lost 8 marbles, George has 3 more marbles than Ahmad. How many marbles did George had at first?
    Ahmad and George had a total of 76 marbles at first. After George bought 15 more marbles and Ahmad lost 8 marbles, George has 3 more marbles than Ahmad. How many marbles did George had at first?

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    0  Views: 285 Answers: 4 Posted: 13 years ago
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      4 Answers

      A + G = 76

      (A - 8) +  (G + 15) = 76 - 8 + 15

      A + G = 83  

      A + (G - 3) = 83 - 3  (The remainder divided by 2 will tell you how many marbles A has)

      A + G = 80  (Half of 80 is 40.  A has 40 marbles.  G has 3 more than A. ( 40 + 3 = 43)


      A has 40 marbles and G has 43. 

      43 - 15 = 28 marbles to start for George.
      Ahmed had 48 marbles to begin with.   28 + 48 = 76

      13 years ago. Rating: 1
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        digger

        But that wasn't the question.
        commented 13 years ago
        Bob/PKB

        OH CRAP. You're right. Back to the drawing board.
        commented 13 years ago

        Off the computer and get to your math homework!

        13 years ago. Rating: 1
        Comment this answer

          George had 28 at first but had to surrender them all to Ahmad after Ahmad threatened to blow up George's XBOX.

          13 years ago. Rating: 1
          Comment this answer

            No use asking me, I lost my marbles years ago.

            13 years ago. Rating: 1
            Comment this answer



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